SOLUTION: Give the exact and approximate solutions to three decimal places. y^2-10y+25=100 equation is ax^2+bx+c I believe ??? I am confused because there are y's and 10 is negative..

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Give the exact and approximate solutions to three decimal places. y^2-10y+25=100 equation is ax^2+bx+c I believe ??? I am confused because there are y's and 10 is negative..      Log On


   

Question 342213: Give the exact and approximate solutions to three decimal places.
y^2-10y+25=100
equation is ax^2+bx+c I believe ??? I am confused because there are y's and 10 is negative...
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Give the exact and approximate solutions to three decimal places.
y^2-10y+25=100
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Factor:
(y-5)^2 - 100 = 0
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Factor
[(y-5)-10][(y-5)+10] = 0
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y-5 = 10 or y-5 = -10
y = 15 or y = -5
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Cheers,
Stan H.
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