SOLUTION: Hi, I need help with: Evaluate the discriminant b^2 - 4ac. Then use the answer to state how many real-number solutions exist for the equation: y = x^2 + 8x + 16 Thanks!

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Question 340339: Hi,
I need help with:
Evaluate the discriminant b^2 - 4ac. Then use the answer to state how many real-number solutions exist for the equation: y = x^2 + 8x + 16
Thanks!
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
This site explains it quite well:
http://www.mathwarehouse.com/quadratic/discriminant-in-quadratic-equation.php
.
A "quadratic" is in the form of:
y = ax^2 + bx + c
.
Given:
y = x^2 + 8x + 16
we now have:
a is 1
b is 8
c is 16
.
Plug into:
b^2 - 4ac
8^2 - 4(1)(16)
64 - 64
0
.
Since "discriminant" is zero
Conclusion:"ONE real solution"