SOLUTION: How can I solve 4x^2 + 48x +104 = 0 by applying the quadratic formula?

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Question 336726: How can I solve 4x^2 + 48x +104 = 0 by applying the quadratic formula?
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!

4x%5E2+%2B+48x+%2B104+=+0

To make things easier, divide every term by 4

4x%5E2%2F4%2B48x%2F4%2B104%2F4=0%2F4

x%5E2%2B12x%2B26=0

a=1, b=12, c=26

x+=+%28-12+%2B-+sqrt%28+12%5E2-4%2A1%2A26+%29%29%2F%282%2A1%29+

x+=+%28-12+%2B-+sqrt%28144-104+%29%29%2F2+

x+=+%28-12+%2B-+sqrt%2840+%29%29%2F2+

x+=+%28-12+%2B-+sqrt%284%2A10%29%29%2F2+

x+=+%28-12+%2B-+2sqrt%2810%29%29%2F2+ 

Factor 2 out of the top:

x+=+%282%28-6+%2B-+sqrt%2810%29%29%29%2F2+

x+=+%28cross%282%29%28-6+%2B-+sqrt%2810%29%29%29%2Fcross%282%29+

x+=+-6+%2B-+sqrt%2810%29%29+

The two solutions are 

x+=+-6+%2B+sqrt%2810%29%29+ and x+=+-6+-+sqrt%2810%29%29+

Edwin