SOLUTION: Use the quadratic formula to solve each: y^2+13y+22=0 x(2x+3)-1=0 x^2+24=0

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Question 334561: Use the quadratic formula to solve each:
y^2+13y+22=0
x(2x+3)-1=0
x^2+24=0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll do the first to get you started. Please only post one problem at a time.


y%5E2%2B13y%2B22=0 Start with the given equation.


Notice we have a quadratic equation in the form of ay%5E2%2Bby%2Bc where a=1, b=13, and c=22


Let's use the quadratic formula to solve for y


y+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


y+=+%28-%2813%29+%2B-+sqrt%28+%2813%29%5E2-4%281%29%2822%29+%29%29%2F%282%281%29%29 Plug in a=1, b=13, and c=22


y+=+%28-13+%2B-+sqrt%28+169-4%281%29%2822%29+%29%29%2F%282%281%29%29 Square 13 to get 169.


y+=+%28-13+%2B-+sqrt%28+169-88+%29%29%2F%282%281%29%29 Multiply 4%281%29%2822%29 to get 88


y+=+%28-13+%2B-+sqrt%28+81+%29%29%2F%282%281%29%29 Subtract 88 from 169 to get 81


y+=+%28-13+%2B-+sqrt%28+81+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


y+=+%28-13+%2B-+9%29%2F%282%29 Take the square root of 81 to get 9.


y+=+%28-13+%2B+9%29%2F%282%29 or y+=+%28-13+-+9%29%2F%282%29 Break up the expression.


y+=+%28-4%29%2F%282%29 or y+=++%28-22%29%2F%282%29 Combine like terms.


y+=+-2 or y+=+-11 Simplify.


So the answers are y+=+-2 or y+=+-11