SOLUTION: The baseball player throws a ball, and the height of the ball (in feet) can be approximated by the quadratic function {{{y(x)=-0.011x^2+0.577x+5}}} where x is the horizontal positi

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Question 331983: The baseball player throws a ball, and the height of the ball (in feet) can be approximated by the quadratic function y%28x%29=-0.011x%5E2%2B0.577x%2B5 where x is the horizontal position of the ball measured in feet from the origin.
A. For what value of x will the ball reach its highest point? round to the nearest foot.
B. What is the maximum height of the ball? round to the nearest tenth of a foot.
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
The baseball player throws a ball, and the height of the ball (in feet) can be approximated by the quadratic function y%28x%29=-0.011x%5E2%2B0.577x%2B5 where x is the horizontal position of the ball measured in feet from the origin.
A. For what value of x will the ball reach its highest point? round to the nearest foot.
.
y(x)=-0.011x^2+0.577x+5
Finding the "vertex" will give you the highest point:
axis of symmetry = -b/(2a)
axis of symmetry = -0.577/(2(-0.011))
axis of symmetry = -0.577/(-0.022)
axis of symmetry = 26.23
x = 26.23 = 26 feet
.
B. What is the maximum height of the ball? round to the nearest tenth of a foot.
To find the height, plug it back in:
y(x)=-0.011x^2+0.577x+5
y(26)=-0.011(26)^2+0.577(26)+5
y(26)= 12.57 = 13 feet