SOLUTION: 2x^2-3x=-7 I was asked to find the solution set. I used the quadratic equation and came up with -3+/- the square of 47/4 right?

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Question 331971: 2x^2-3x=-7 I was asked to find the solution set. I used the quadratic equation and came up with -3+/- the square of 47/4 right?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2-3x=-7
2x%5E2+-+3x+%2B+7+=+0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 2x%5E2%2B-3x%2B7+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-3%29%5E2-4%2A2%2A7=-47.

The discriminant -47 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -47 is + or - sqrt%28+47%29+=+6.85565460040104.

The solution is , or
Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B-3%2Ax%2B7+%29

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That's close.