Question 329015: solve for x providing exact answers using radicals as needed for the following equation x^2+12x+1=36 Found 2 solutions by stanbon, mananth:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! solve for x providing exact answers using radicals
as needed for the following equation x^2+12x+1=36
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x^2 + 12x - 35 = 0
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a = 1 ; b = 12 ; c = -35
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x = [-12 +- sqrt(144 -4*-35)]/2
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x = [-12 +- sqrt(284)]/2
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x = [-12 +- 2sqrt(71)]/2
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x = [-6 +- sqrt(71)]
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Cheers,
Stan H.
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You can put this solution on YOUR website! x^2+12x+1=36
x^2+12x+1-36=0
x^2+12x-35=0
find the roots of the equation using formula
a=1b=12c=-35
x = [-12 +- sqrt(144 -4*-35)]/2
..
x = [-12 +- sqrt(284)]/2
..
x = [-12 +- 2sqrt(71)]/2
..
x = [-6 +- sqrt(71)]
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