Question 324243: x2+x-3=3 solution
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! This is NOT a LINEAR equation!! Because of the x^2 in the problem, it is a QUADRATIC EQUATION, which must be solved by completely different methods. The first step, you must set the equation equal to zero. In this case, subtract 3 from each side:
x^2+x-3=3
x^2+x-3-3=3-3
x^2+x-6=0
Next, you have to HOPE that the trinomial on the left side of the equation will FACTOR! In this case IT DOES!!
(x+3)(x-2)=0
Next, set each factor equal to zero, and solve:
x+3=0
x=-3
x-2=0
x=2
By the way, I think I have a fairly simple explanation of this topic that you may find easier to understand than your own textbook! Go to my website by clicking on my tutor name "rapaljer" anywhere in algebra.com. Then click on my website that will be given there.
From the Homepage of my website, look for the link "Basic, Intermediate, and College Algebra: One Step at a Time." Choose "Basic Algebra". There you will find my COMPLETE curriculum for first level algebra. This topic of Quadratic Equations just happens to be in Chapter 2, so click on "Chapter 2" and look for "Section 2.09 Solving Quadratic Equations by Factoring." There you will find my own explanation of this topic, which I wrote especially for students who have trouble understanding math! Also, a LOT of the problems here are solved in the "MATH IN LIVING COLOR" pages that go with the sections in this curriculum.
I really believe math is NOT as hard as it looks, and if you get a good explanation, you CAN do it!! Get lots of help, and get lots of practice. If you like the website, please recommend my website to family and friends!!
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
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