SOLUTION: f(x)= (x+5)^2-2 The vertex is (ordered pair) the min value is f(x) =

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: f(x)= (x+5)^2-2 The vertex is (ordered pair) the min value is f(x) =      Log On


   

Question 323624: f(x)= (x+5)^2-2
The vertex is (ordered pair)
the min value is f(x) =
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The equation is in vertex form.
Vertex : (-5,-2)
The minimum value occurs at the vertex since the parabola opens upwards.
fmin=-2