SOLUTION: y^4+y^2-36=0

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Question 322132: y^4+y^2-36=0
Answer by checkley77(12844) About Me  (Show Source):
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y^4+y^2-36=0
y%5E2+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
y^2=(-1+-sqrt1^2-4*1*-36])/2*1
y^2=(-1+-sqrt[1+144])/2
y^2=(-1+-sqrt145)/2
y^2=-1+-12.0416)/2
y^2=(-1+12.0416)/2
y^2=11.0416/2
y^2=5.52
y=sqrt5.52
y=2.35 ans.
y^2=(-1-12.0416)/2
y^2=-13.0416/2
y^2=--6.52
y=sqrt-6.52
y=2.55i ans.