Question 315258: A sandbag falls out of a hot air balloon that is 144 feet above the ground how long does it take for the sandbag to reach the ground? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! h(t) = -(1/2)32t^2 + Vt + Ho
where
h(t) is height
t is time
V is initial velocity (0)
Ho is initial height (144)
.
0 = -(1/2)32t^2 + 0t + 144
0 = -16t^2 + 144
-144 = -16t^2
9 = t^2
3 sec = t
