SOLUTION: how do you get the x intercepts by evaluating the function in order to get other points to graph the function>??????
this is what I have so far:
f(x) =2x^2 +2
=2(x^2 +1)
Question 313133: how do you get the x intercepts by evaluating the function in order to get other points to graph the function>??????
this is what I have so far:
f(x) =2x^2 +2
=2(x^2 +1) +2
f(x) = 2(x^2+1+.5-.5)+2
=2(x+2+1)+3(.5)+2
=2(x+3)^2 + 3.5
am i on the right track and if so what next in order to finish ?? Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! No, not on the right track.
To get x-intercepts, set f(x)=y=0 and solve for x.
Well there are no x such that when you square them and add 2 will give you zero. There are no x-intercepts for this parabola.
It never crosses the x-axis.
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To get the y-intercept, set x=0 and solve for y.
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You can find the axis of symmetry and vertex by completing the square.
Actually, it's already in vertex form,
So the vertex is at (0,2) and it opens upwards.
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To get other points, just pick an x and calculate y. , ,
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