SOLUTION: Without graphing, find the maximum value. f(x) = -10/3(x + 5)^2 - 5

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Without graphing, find the maximum value. f(x) = -10/3(x + 5)^2 - 5      Log On


   

Question 312543: Without graphing, find the maximum value.
f(x) = -10/3(x + 5)^2 - 5
Found 2 solutions by Fombitz, solver91311:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The max occurs at the vertex, when x=-5.
fmax=f%28-5%29=-5

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Re-write your function:



Since the lead coefficient is negative, this parabola opens downward making the vertex a maximum.

The vertex form equation of a parabola with vertical axis symmetry like this one is:



Your vertex is therefore at

The -coordinate of the vertex is the value of the function at the vertex, so:



John