SOLUTION: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimeter longer and 2 centimeters wider than the first. The area of the second rectangle is 530 square centi

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimeter longer and 2 centimeters wider than the first. The area of the second rectangle is 530 square centi      Log On


   

Question 306973: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimeter longer and 2 centimeters wider than the first. The area of the second rectangle is 530 square centimeters greater than the first. What are the dimensions of the original rectangle?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let the width of the rectangle be x
the length will be 4x
.
second rectangle
Width will be x+2
Length will be 4x+5
(4x+5)(x+2)-530=4x*x
4x^2+13x+10-530=4x^2
13x=520
x=40 cm which is the width
length = 4x
=160 cm.