SOLUTION: find the real solutions, using the quadratic equation 3x(x+2)=1

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Question 304624: find the real solutions, using the quadratic equation
3x(x+2)=1

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
find the real solutions, using the quadratic equation
3x(x+2)=1
Convert equation to the standard form: ax^2 + bx + c = 0
3x^2 + 6x - 1 = 0
The quadratic formula:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
in this problem: a=3; b=6; c=-1
x+=+%28-6+%2B-+sqrt%28+-6%5E2+-+4%2A3%2A-1+%29%29%2F%282%2A3%29+
:
x+=+%28-6+%2B-+sqrt%2836+-+%28-12%29+%29%29%2F6+
:
x+=+%28-6+%2B-+sqrt%2836+%2B+12+%29%29%2F6+
:
x+=+%28-6+%2B-+sqrt%2848+%29%29%2F6+
Two solutions
x+=+%28-6+%2B+6.928%29%2F6+
x = .928%2F6
x = .15467
and
x+=+%28-6+-+6.928%29%2F6+
x = %28-12.928%29%2F6
x = -2.15467