Question 29903: Please would anybody help me solve this problem I would appreciate it very much
Thank you
-x^2+3x-2=0 Found 3 solutions by Cintchr, Earlsdon, sdmmadam@yahoo.com:Answer by Cintchr(481) (Show Source):
You can put this solution on YOUR website! first .... multiply each part by -1 to turn the first term positive. factor set each piece equal to zero and and
You can put this solution on YOUR website! Solve: Factor out -1. Divide both sides by -1. Factor. Apply the zero products principle. and/or
If then
If then
The roots are:
x = 1
x = 2
You can put this solution on YOUR website! -x^2+3x-2=0
Multiplying by (-1)
x^2-3x+2 = 0 ----(1)
x^2-2x-x+2 =0 [splitting the middle term and expressing it as the sum of two terms so that their product is the product of the square term and the constant term. Here (-3x) = (-2x)+(-x) and (-2x)X(-x) = 2x^2 = (x^2)X(2)]
(x^2-2x)-x+2 =0 (by additive associativity)
x(x-2)-1(x-2)=0 (why (-1) pulled out? so that to get(x-2)! )
xp-p= 0 where p= (x-2)
p(x-1) = 0 (taking p out)
(x-2)(x-1) = 0 (putting t back)
(x-2) = 0 gives x = 2
(x-1) = 0 gives x = 1
Answer: x = 1 and x = 2
Verification: x = 1 in (1)
LHS = 1-3+2 = 0 = RHS
x = 2 in (1)
LHS = 4-6+2 = 0=RHS
(
