SOLUTION: Suppose to want to reserve a rectangular region in a large room and you have 32 ft. of masking tape. Let’s investigate how much area you can reserve with 32 ft. of masking tape an

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Suppose to want to reserve a rectangular region in a large room and you have 32 ft. of masking tape. Let’s investigate how much area you can reserve with 32 ft. of masking tape an      Log On


   



Question 298215: Suppose to want to reserve a rectangular region in a large room and you have 32 ft. of masking tape. Let’s investigate how much area you can reserve with 32 ft. of masking tape and how this area changes with different lengths of sides for the rectangular region.
1) Take a guess on the dimensions of the region that would give the largest area.
2) Find the values for the table below. The column labels of base, height, and area represent the values of the base height and area of the rectangular region. Use as many different values of bases and heights as you can, but have the perimeter or the rectangular region be 32ft. The table could not be put on here but it kind of looks like this:
Base Height Area

Someone please help! Thank you!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose to want to reserve a rectangular region in a large room and you have 32 ft. of masking tape. Let’s investigate how much area you can reserve with 32 ft. of masking tape and how this area changes with different lengths of sides for the rectangular region.
1) Take a guess on the dimensions of the region that would give the largest area.
2) Find the values for the table below. The column labels of base, height, and area represent the values of the base height and area of the rectangular region. Use as many different values of bases and heights as you can, but have the perimeter or the rectangular region be 32ft. The table could not be put on here but it kind of looks like this:
Perimeter = 2L + 2W
Base:::::::::::::::::::Height::::::::::::::::::::Area
1.......................15........................15
2.......................14........................28
3.......................13........................39
etc.
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Cheers,
Stan H.