SOLUTION: (x^2-x)^2 - 14(x^2-x) + 24 = 0

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Question 29809: (x^2-x)^2 - 14(x^2-x) + 24 = 0
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
+%28x%5E2-x%29%5E2+-+14%28x%5E2-x%29+%2B+24+=+0+
first, distribute the power on the first quantity by multiplying the exponents.
+%28x%5E4-x%5E2%29+-+14%28x%5E2-x%29+%2B+24+=+0+ the distribute the 14 to the quantity dont forget to watch your signs
+%28x%5E4-x%5E2%29+-+14x%5E2%2B14x+%2B+24+=+0+ combine like terms
+%28x%5E4%29+%2B+highlight+%28-1x%5E2+-+14x%5E2%29+%2B+14x+%2B+24+=+0+
+x%5E4+-+15x%5E2+%2B+14x+%2B+24+=+0+ with 4 terms, you have to factor two of them at a time to find a common factor
+highlight+%28x%5E4+-+15x%5E2%29+%2B+highlight+%2814x+%2B+24%29+=+0+
+x%5E2%28x%5E2+-+15%29+%2B+2%287x+%2B+12%29+=+0+ I can not get it to factor from here. Check your signs in the original problem. Are they correct?