SOLUTION: 2x^2 + 7x-9=2x^2-18
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Question 2969
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2x^2 + 7x-9=2x^2-18
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2x^2 + 7x-9=2x^2-18
equate to zero
2x^2 + 7x-9-2x^2+18=0
7x-9+18=0
7x+9=0
7x=-9
x=-9/7