Question 292771: How do you solve the equation by completing the square, w^2-14w+24=0 ?
Answer by dabanfield(803)   (Show Source):
You can put this solution on YOUR website! w^2-14w+24=0
1.) w^2 - 14w = -24
We need to add the same constant to both sides to get the left side to factor into (x-a)^2
If we take half the coefficent on w (that is -14) and then square it we will have the constant we are looking for. -14/2 = -7. If we square -7 we get 49. So we will add 49 to both sides of 1.):
w^2 - 14w + 49 = -24 + 49
(w-7)^2 = 25
w-7 = sqrt(25) or w-7 = -sqrt(25)
w-7 = 5 or w-7 = -5
w = 12 or w = 2
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