SOLUTION: Hi tutor please help me with this problem. Put the equation in the form ax2 + bx + c = 0. Use the caret (^) to enter exponents. For example, enter x2 as x^2 Question: x^2 + 8x

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Question 290950: Hi tutor please help me with this problem. Put the equation in the form ax2 + bx + c = 0. Use the caret (^) to enter exponents. For example, enter x2 as x^2

Question: x^2 + 8x + 10 = 3

(x*2)(x*2)=4x
4x+8x+10=3
-3 -3
4x+8x+7=0
Found 2 solutions by ankor@dixie-net.com, Deina:
Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
Question: x^2 + 8x + 10 = 3
Subtract 3 from both sides
x^2 + 8x + 10 - 3 = 0
:
x^2 + 8x + 7 = 0; this is the ax^2 + bx + c = 0 form
Factors to
(x+7)(x+1) = 0
Two solutions
x = -7
and
x = -1
:
:
"(x*2)(x*2)=4x
4x+8x+10=3
-3 -3
4x+8x+7=0"
I am not sure what all this means

Answer by Deina(147) (Show Source):
You can put this solution on YOUR website!

& bob's your uncle!

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=36 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: -1, -7. Here's your graph: