SOLUTION: The value of a share can be represented by V(x) = x2 – 28x + 13, where x is the number of months after January 2004. What is the lowest value V(x) will reach, and when did that oc

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The value of a share can be represented by V(x) = x2 – 28x + 13, where x is the number of months after January 2004. What is the lowest value V(x) will reach, and when did that oc      Log On


   

Question 289806: The value of a share can be represented by V(x) = x2 – 28x + 13, where x is the number of months after January 2004. What is the lowest value V(x) will reach, and when did that occur? (5 points)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
+V%28x%29+=+x%5E2-28x+%2B+13+
You can take the derivative and set it equal to zero to find extrema.
dV%2Fdx=2x-28=0
2x-28-0
2x=28
x=14
Since V''(x)=2, then the extrema is a minimum.
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You can also check it graphically.
+graph%28+300%2C+300%2C+-7%2C+28%2C+-200%2C+100%2C+x%5E2-28x+%2B+13+%29+