SOLUTION: The sum of the squares of two consecutive integers is 41. Find the integers

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The sum of the squares of two consecutive integers is 41. Find the integers      Log On


   

Question 288: The sum of the squares of two consecutive integers is 41. Find the integers
Answer by ichudov(507) About Me  (Show Source):
You can put this solution on YOUR website!
You have two consecutive integers, number and number+1. The sum of their squares is number%5E2+%2B+%28number%2B1%29%5E2. Since it is 41, we have
number%5E2+%2B+%28number%2B1%29%5E2+=+41 or
number%5E2%2B+%28number%5E2%2B2number%2B1%29+=+41
or
2number%5E2%2B2number+-40
Solve it using my quadratic solver. (the solution is pretty obvious, 4 and 5, it is just as easy to try the first few numbers without writing an equation)