SOLUTION: 3x^3+4x^2-32x=0

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Question 282233: 3x^3+4x^2-32x=0
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
3x^3+4x^2-32x=0
.
separate the common 'x'
.
x*(3x^2+4x-32)=0
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factor
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(3x^2+4x-32)=(3x - 8 )(x + 4)
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so...
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x(3x-8)(x+4)=0
.
That means there are three roots:
x = 0
x = 8/3
x = -4
.
graph%28500%2C500%2C-10%2C10%2C-70%2C70%2C3%2Ax%5E3%2B4x%5E2-32%2Ax%29