SOLUTION: Evaluate h(x) = x2 – 4x + 5 h(4) = h(–4) = h(0) =
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-> SOLUTION: Evaluate h(x) = x2 – 4x + 5 h(4) = h(–4) = h(0) =
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Question 280211
:
Evaluate
h(x) = x2 – 4x + 5
h(4) =
h(–4) =
h(0) =
Found 2 solutions by
solver91311, JBarnum
:
Answer by
solver91311(24713)
(
Show Source
):
You can
put this solution on YOUR website!
If
Then
So
and
Congratulations, you get to do your very own arithmetic.
John
Answer by
JBarnum(2146)
(
Show Source
):
You can
put this solution on YOUR website!
simply replace the x with the value given and solve
h(x)= x^2–4x+5
h(4)= (4^2)–4(4)+5 = 16-16+5 = 5
h(–4)= (-4)^2–4(-4)+5 = 16+16+5 = 37
h(0)= 0^2–4(0)+5 = 5