Question 279734: How would I find the x-intercepts for the quadratic equations:
6x^2 - 7x + 2 = 0
5x^2 – 21x + 4 = 0
4x^2 – 3x - 1 = 0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! How would I find the x-intercepts for the quadratic equations:
Factor and solve:
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6x^2 - 7x + 2 = 0
(6x^2 -3x-4x +2 = 0
3x(2x-1)-2(2x-1) = 0
(2x-1)(3x-2) = 0
x = 1/2 or x = 2/3
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5x^2 – 21x + 4 = 0
5x^2-20x-x+4 = 0
5x(x-4)-(x-4) = 0
(x-4)(5x-1) = 0
x = 4 or x = 1/5
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4x^2 – 3x - 1 = 0
4x^2 -4x+x - 1 = 0
4x(x-1)+(x-1) = 0
(x-1)(4x+1) = 0
x = 1 or x = -1/4
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Cheers,
Stan H.
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