SOLUTION: need help solving negative b+ or minus square root of b squared - 4ac over 2a

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Question 279624: need help solving negative b+ or minus square root of b squared - 4ac over 2a
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
your quadratic formula is:

x = %28-b+%2B-+sqrt%28b%5E2-4ac%29%29%2F%282a%29

your quadratic equation has to be in the form of:

ax^2 + bx + c = 0

a is the coefficient of the x^2 term.
b is the coefficient of the x term.
c is the constant term.

you find the values of a,b,c and plug them into the formula.

an example:

x^2 - 4x + 3 = 0

a = 1
b = -4
c = 3

the quadratic formula is:

x = %28-b+%2B-+sqrt%28b%5E2-4ac%29%29%2F%282a%29

if b is equal to -4, then -b is equal to 4.
if a is equal to 1, then 2a is equal to 2.
if b is equal to -4, then b^2 is equal to 16.
if a is equal to 1 and c is equal to 3, then 4ac is equal to 4*1*3 = 12

you plug these values into your quadratic formula to get:

x = %284+%2B-+sqrt%2816-12%29%29%2F%282%29

you simplify this equation to get:

x = %284+%2B-+sqrt%284%29%29%2F%282%29

you simplify this equation further to get:


x = %284+%2B-+2%29%2F%282%29

this becomes x = 6/2 = 3, or x = 2/2 = 1

x is either equal to 1 or x is equal to 3.

a graph of the equation y = x^2 - 4x + 3 looks like this:

graph%28600%2C600%2C-10%2C10%2C-10%2C10%2Cx%5E2+-+4x+%2B+3%29

you can see from the graph that y crosses he x-axis when x = 1 and when x = 3.

x = 1 and x = 3 are the roots of your equation.

using the quadratic formula is simply a matter of plugging in the right values for a,b,c in the equation and then solving it.