SOLUTION: what are the coordinates of the vertex of p=-1/2s^2+280s-1200

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Question 277103: what are the coordinates of the vertex of
p=-1/2s^2+280s-1200
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
It's the same as all of them, at s = -b/2a
s = -280/(-2*(-1/2)) = 280
Sub 280 for s, find p
That's it.