SOLUTION: Can someone please help me with this problem? Multiply: 3y^2+13y+14 divided by y^2+3y+2 * 2y^2-3y-2 divided by 3y^2+22y+35 This is what I came up with. Is this correct? (y+2

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Can someone please help me with this problem? Multiply: 3y^2+13y+14 divided by y^2+3y+2 * 2y^2-3y-2 divided by 3y^2+22y+35 This is what I came up with. Is this correct? (y+2      Log On


   



Question 273268: Can someone please help me with this problem?
Multiply: 3y^2+13y+14 divided by y^2+3y+2 * 2y^2-3y-2 divided by 3y^2+22y+35

This is what I came up with. Is this correct?
(y+2)(3y+7)divided by (y+2)(y+1) * (y-2)(2y+1) divided by (3y+7)(y+5) equals to (y-2)(2y+1) divided by (y+1)(y+5)

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
This is what I came up with. Is this correct?
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Your factoring is correct.
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[(y+2)(3y+7)]/[(y+2)(y+1)] * [(y-2)(2y+1)]/[(3y+7)(y+5)]
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Cancel the y+2 factor:
Cancel the 3y+7 factor:
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(1/(y+1)
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equals to (y-2)(2y+1) divided by (y+1)(y+5)
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You are correct.
Cheers,
Stan H.