SOLUTION: Write a quadratic equation in the variable X having the given numbers as solutions. Type the equation in standard form of ax^2+bx+c=0. Solution: 1, only solution The equatio

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Write a quadratic equation in the variable X having the given numbers as solutions. Type the equation in standard form of ax^2+bx+c=0. Solution: 1, only solution The equatio      Log On


   

Question 271920: Write a quadratic equation in the variable X having the given numbers as solutions. Type the equation in standard form of ax^2+bx+c=0.
Solution: 1, only solution
The equation is _____________ =0
Thanks so much for your help :-)
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
Quadratic equations have two solutions. And the equation
%28x-r%5B1%5D%29%28x-r%5B2%5D%29+=+0
is a general form for quadratic equations where the solutions (r%5B1%5D and r%5B2%5D) can be seen.

Sometimes the solution is "of multiplicity two". This means that there is just one number that counts twice as a solution. In other "words", r%5B1%5D+=+r%5B2%5D. Since your problem claims to have just one solution, 1, it must be a solution of multiplicity two. And the equation would be:
%28x-1%29%28x-1%29=0
which simplifies to:
x%5E2+-2x+%2B1+=+0