SOLUTION: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers. So, um yeah I don't get this one at all.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers. So, um yeah I don't get this one at all.      Log On


   

Question 27097: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
So, um yeah I don't get this one at all.
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
LEt the three integers be x, x+2 and x+4

%28x%2B4%29%5E2=76%2B%28x%2B2%29%5E2
x%5E2%2B8x%2B16=76%2Bx%5E2%2B4x%2B4
x%5E2-x%5E2%2B8x-4x=76%2B4-16
4x=64
x=16

16+2=18
16+4=20
Hence, the three consecutive integers are 16, 18 and 20.
Paul.