SOLUTION: how can I factor 4x^2+16x+13?

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Question 270291: how can I factor 4x^2+16x+13?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression 4x%5E2%2B16x%2B13, we can see that the first coefficient is 4, the second coefficient is 16, and the last term is 13.



Now multiply the first coefficient 4 by the last term 13 to get %284%29%2813%29=52.



Now the question is: what two whole numbers multiply to 52 (the previous product) and add to the second coefficient 16?



To find these two numbers, we need to list all of the factors of 52 (the previous product).



Factors of 52:

1,2,4,13,26,52

-1,-2,-4,-13,-26,-52



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to 52.

1*52 = 52
2*26 = 52
4*13 = 52
(-1)*(-52) = 52
(-2)*(-26) = 52
(-4)*(-13) = 52


Now let's add up each pair of factors to see if one pair adds to the middle coefficient 16:



First NumberSecond NumberSum
1521+52=53
2262+26=28
4134+13=17
-1-52-1+(-52)=-53
-2-26-2+(-26)=-28
-4-13-4+(-13)=-17




From the table, we can see that there are no pairs of numbers which add to 16. So 4x%5E2%2B16x%2B13 cannot be factored.



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Answer:



So 4%2Ax%5E2%2B16%2Ax%2B13 doesn't factor at all (over the rational numbers).



So 4%2Ax%5E2%2B16%2Ax%2B13 is prime.