SOLUTION: {{{3x^2-9x+5<0}}} It has been years since I have had an algebra class. I cannot remember how to solve this problem. Thank You!

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Question 27: 3x%5E2-9x%2B5%3C0
It has been years since I have had an algebra class. I cannot remember how to solve this problem. Thank You!
Found 2 solutions by ichudov, jam123:
Answer by ichudov(507) About Me  (Show Source):
You can put this solution on YOUR website!
Draw a graph of x%5E2-9x%2B5:
graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2-9x%2B5%29+
The area between the roots where the graph goes below the x axis, is the solution. In your case, it seems that there are no roots and therefore, no points such that the graph goes below zero. So, your answer is that the solution is an empty set.

Answer by jam123(18) About Me  (Show Source):
You can put this solution on YOUR website!
3x%5E2-9x%2B5%3C0
Sorry if the question is answered already but,
You are going to switch +5 over to the other side, substituting +5 with -5
So pretty much 3x%5E2-9x%3C-5.
And 3x%5E2-9x is smaller than -5! x might have to be a negative.
Let's try -1.
9 - -9 < -5
or
18 is smaller than -5
NOT!
How about -2?
36 - -18 is smaller than -5
or
54 is smaller than -5
OF COURSE NOT!
So we might have to try a positive for x.
Try 1!
9 - 9 is smaller than -5
or
0 is smaller than -5
NOT!
Try 2!
36 - 18 is smaller than -5
or
18 is smaller than -5
NOT!
What can we do?
Just so we remember,
3x%5E2-9x%3C-5
How about we switch - with +?
3x%5E2%2B9x%3C5
So, the only possible answer is that x=0!
EDIT
Actually, x does NOT equal 0! I just figured.
3x%5E2-9x%2B5%3C0
Why don't we try -1 again?
9+-+-9++%2B+5%3C0
or
23%3C0
NOPE!
No! It has to be an imaginary! (I think)