SOLUTION: Please help me solve this equation: {{{ (t+4)^2-16=0 }}}.
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Question 268826
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Please help me solve this equation:
.
Answer by
mananth(16946)
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Please help me solve this equation:
.
(t+4)^2-16=0 -----------a^2-b^2= (a+b)(a-b)
((t+4+4)(t-4-4))=0
(t+8)t=0
t=0 or -8