SOLUTION: Some students planned for a get-together. The budget for food was $500. Five of the students failed to come because of the distance, and therefore the cost of food for each member

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Some students planned for a get-together. The budget for food was $500. Five of the students failed to come because of the distance, and therefore the cost of food for each member       Log On


   

Question 26693: Some students planned for a get-together. The budget for food was $500. Five of the students failed to come because of the distance, and therefore the cost of food for each member increased by $5. How many students attended the get-together?
How in the world do you do this? lol HELP!
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
Normal = x
When 5 students failed = x-5
Total = 500
Increased by 5 = +5
500%2Fx-500%2F%28x-5%29=5
500[(x)-(x-5)]=5[(x)(x-5)]
500%285%29=5%28x%5E2-5x%29
2500=5x%5E2-25x
5x%5E2-25x-2500
x%5E2-5x-500=0%2Cx
Facotr the quadratic equation:
(x+20)(x-25)
x=-20 and x= 25
Remove the negative. And:
Hence, the total number of students were 25.
Paul.