SOLUTION: The coefficients of a quadratic equation are positive integers and the difference between the two roots of the equation is 2. If one of the roots is -3/4, find the equation.

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Question 265412: The coefficients of a quadratic equation are positive integers and the difference between the two roots of the equation is 2. If one of the roots is -3/4, find the equation.
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
The coefficients of a quadratic equation are positive integers and the difference between the two roots of the equation is 2. If one of the roots is -3/4, find the equation.


There are two possibilities to consider, depending on which way 
subtracting them gives 2:

Case 1.  The roots are 3%2F4 and 3%2F4%2B2, or 11%2F4
Case 2.  The roots are 3%2F4 and 3%2F4-2, or -5%2F4

In case 1, the difference between the roots is 11%2F4-3%2F4=8%2F4=2
In case 2, the difference between the roots is 3%2F4-%28-5%2F4%29=3%2F4%2B5%2F4=8%2F4=2

In case 1, the solutions would be

x=11%2F4 and x=3%2F4

or

4x=11 and 4x=3

or

4x-11=0 and 4x-3=0

which would have come from using the zero-factor 
property of the factored equation:

%284x-11%29%284x-3%29=0

which would have come from the quadratic equation:

16x%5E2-12x-44x%2B33=0

or

16x%5E2-56x%2B33=0 

But the problem said that the coefficients are positive 
integers.  But -56 is not positive.  So we have to discard that answer.

---

In case 2, the solutions would be

x=3%2F4 and x=-5%2F4

or

4x=3 and 4x=-5

or

4x-3=0 and 4x%2B5=0

which would have come from using the zero-factor 
property of the factored equation:

%284x-3%29%284x%2B5%29=0

which would have come from the quadratic equation:

16x%5E2%2B20x-12x-15=0

or

16x%5E2%2B8x-15=0 

The coefficients of x%5E2 and x are both
positive. So that is the only quadratic equation
with the coefficients of x%5E2 and x both
positive integers. 

Edwein