SOLUTION: Write a quadratic expression having the given numbers as solutions 3/5, -9

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Write a quadratic expression having the given numbers as solutions 3/5, -9      Log On


   

Question 263326: Write a quadratic expression having the given numbers as solutions
3/5, -9
Found 2 solutions by Alan3354, richwmiller:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
It's always
(x - a)*(x - b) = 0 where a and b are the solutions
(x - 3/5)*(x + 9) = 0
(5x-3)*(x+9) = 0
5x%5E2+%2B+42x+-+27+=+0

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
(x-3/5)(x+9)=0
1/5(x+9)*(5x-3)=0
(x+9)*(5x-3) = 0
x^2+(42x)/5-27/5 = 0
They are the same.