Question 258019: 3x^2-3x-8=2x^2+2
Answer by unlockmath(1688)   (Show Source):
You can put this solution on YOUR website! Hello,
First, let's get all the terms on one side.
3x^2-3x-8=2x^2+2 Subtract 2x^2 and 2 from both sides to give us:
x^2-3x-10=0 Now we can factor this into:
(x-5)(x+2)=0 Now solve x
x=5
x=-2
To check to see if these are correct, plug each into the original equation.
RJ
Check out a new book I wrote at:
www.math-unlock.com
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