SOLUTION: I am thinking of three consecutive numbers. If I multiply the first with the second and then subtract three times the third, the result is 57. What are the numbers? Can someone ple

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: I am thinking of three consecutive numbers. If I multiply the first with the second and then subtract three times the third, the result is 57. What are the numbers? Can someone ple      Log On


   

Question 256296: I am thinking of three consecutive numbers. If I multiply the first with the second and then subtract three times the third, the result is 57. What are the numbers? Can someone please show me the steps to get to the answer? Thank you.
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
Let the numbers be x, x+1 and x+2.
x(x+1)-3(x+2)=57
x^2+x-3x-6=57
x^2-2x-6=57
x^2-2x-63=0
(x-9)(x+7)=0
x=9, x=-7 Two different sets of correct answers: 9, 10, 11 and -7, -6, -5
.
Ed