SOLUTION: the area of a rectangle is 2x^2 - 11x + 15 square feet. The length of the rectangle is 2x - 5 feet. What is the width of the rectangle?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: the area of a rectangle is 2x^2 - 11x + 15 square feet. The length of the rectangle is 2x - 5 feet. What is the width of the rectangle?      Log On


   

Question 254255: the area of a rectangle is 2x^2 - 11x + 15 square feet. The length of the rectangle is 2x - 5 feet. What is the width of the rectangle?
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
We can find the answer using factoring:
2x%5E2+-+11x+%2B+15
factors to
%282x-5%29%28x-3%29
This is over length of
%282x-5%29
we get
x-3 as the width.