Question 254215: For each of the following quadratics,
A. y=-2(x+1)^2+8
B. y=x^2+6x-16
- Find the coordinates of the vertex
- Direction of opening
- Identify if the graph is wider or narrower than normal
- Find the equation of the axis of symmetry
- Find the y-intercept
- Find the x-intercept
- Give the domain and range for each quadratic
- Draw a sketch of the quadratic. Be sure to label the vertex and axis of symmetry clearly. Use the staircase method, the x-intercepts or a point of the axis of symmetry to find the actual width of the graph.
Answer by drk(1908)   (Show Source):
You can put this solution on YOUR website! A. y=-2(x+1)^2+8
- Find the coordinates of the vertex
vertex: (-1,8)
- Direction of opening
opens down because of (-) in front of 2.
- Identify if the graph is wider or narrower than normal
Skinny because 2 > 1
- Find the equation of the axis of symmetry
Axis of symmetry is x = -1
- Find the y-intercept
(0,6)
- Find the x-intercept
(-1,0)(-3,0)
- Give the domain and range for each quadratic
domain: all reals
range: Y<= 8
Draw a sketch of the quadratic
B. y=x^2+6x-16
FIrst we complete the square to get vertex form as:
y = (X+3)^2-25
- Find the coordinates of the vertex
vertex: (-3,-25)
- Direction of opening
opens up
- Identify if the graph is wider or narrower than normal
normal opening
- Find the equation of the axis of symmetry
axis of symmetry is x = -3
- Find the y-intercept
(0,-16)
- Find the x-intercept
(2,0) (-8,0)
- Give the domain and range for each quadratic
domain: all reals
range: y >= -25
- Draw a sketch of the quadratic
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