SOLUTION: What is the value of x in m=(4x)^3+b/a^2+b=(20)?

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Question 252607: What is the value of x in m=(4x)^3+b/a^2+b=(20)?
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Here is our formula:
m=%284x%29%5E3%2Bb%2Fa%5E2%2Bb=%2820%29
I will assume just the a is squared and not the fraction (a/b).
One problem I notice here is that there are 2 = signs. Secondly, there is an "m". I don't know how that fits in.
I will assume you want the value of x for the following equation:
%284x%29%5E3%2Bb%2Fa%5E2%2Bb=%2820%29.
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64x%5E3+=+20+-+b+-+b%2Fa%5E2
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x%5E3+=+%2820a%5E2+-+ba%5E2+-+b%29%2F64
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x+=+cube+root+%28%2820a%5E2+-ba%5E2+-+b%29%2F64%29
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At this point I don't know if we are done or you want to find a function in terms of and b that produces perfect cube roots for x.