SOLUTION: The so called golden rectangle is said to be extremely pleasing visually and was used often by ancient Greek and Roman Architects. The length of a golden rectangle is approx. 1.6 t

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Question 248644: The so called golden rectangle is said to be extremely pleasing visually and was used often by ancient Greek and Roman Architects. The length of a golden rectangle is approx. 1.6 times the width. Find the dimensions of a golden rectangle if its area is 9000m^2.
Found 2 solutions by josmiceli, dabanfield:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let l = length
Let w = width
l%2Aw+=+9000 m2
given:
l+=+1.6w
%281.6w%29%2Aw+=+9000
1.6w%5E2+=+9000
w%5E2+=+5625
w+=+75
l+=+1.6w
l+=+1.6%2A75
l+=+120
The length is 120 m and the width is 75 m

Answer by dabanfield(803) About Me  (Show Source):
You can put this solution on YOUR website!
Area of the rectangle is 9000 sq meter.
Let x be the width if the rectangle.
The length then is (1.6)*x
Area - Length times Width = x*(1.6)*x = 9000
So we have:
(1.6)*(x^2) = 9000
Solve for x to get the width then substitute that value in (1.6)*x to get the length.