SOLUTION: width of a triangle is 2ft less than the length, area is 24f^2, L=, w=
Algebra
->
Quadratic Equations and Parabolas
->
Quadratic Equations Lessons
->
Quadratic Equation Lesson
-> SOLUTION: width of a triangle is 2ft less than the length, area is 24f^2, L=, w=
Log On
Quadratics: solvers
Quadratics
Practice!
Practice
Answers archive
Answers
Lessons
Lessons
Word Problems
Word
In Depth
In
Click here to see ALL problems on Quadratic Equations
Question 246162
:
width of a triangle is 2ft less than the length, area is 24f^2, L=, w=
Answer by
checkley77(12844)
(
Show Source
):
You can
put this solution on YOUR website!
W=L-2
LW=AREA
L(L-2)=24
L^2-2L-24=0
(L-6)(L+4)
L-6=0
L=6 ANS. FOR THE LENGTH.
W=6-2=4 ANS. FOR THE LENGTH.
PROOF:
6*4=24
24=24