Question 246091: 8x^2-18xy+9y^2...I have tried to solve this such as 8x^2-18xy+9y^2
x=2 and y=3
8(2)^2-18(2*3)+9(3)^2
From then on, I am lost and I do not even know if
what I had been doing is right.
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! How did you get x=2 & y=3?
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8x^2-18xy+9y^2=0
(4x-3)(2x-3)=0
4x-3=0
4x=3
x=3/4 ans. y=1 & y=.5
2x-3=0
2x=3
x=3/2 ans. y=2 & y=1.
8(3/4)^2-18(3/4y)+9y^2=0
8*9/16-54/4y+9y^2=0
72/16-27y/2+9y^2=0
9y^2-27y/2+9/2=0
9(y^2-3y/2+1/2)=0
9(y^2-1.5y+.5)=0
9(y-1)(y-.5)=0
y-1=0
y=1 ans
y-.5=0
y=.5 ans.
8(3/2)^2-18(3/2y)+9y^2=0
8*9/4-27y+9y^2=0
18-27y+9y^2=0
9y^2-27y+18
9(y^2-3y+2)=0
(y-2)(y-1)=0
y-2=0
y=2 ans
y-1=0
t=1 ans
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