SOLUTION: i have -16x^2+88x+3=124 and i have to use the quadratic formula to solve the equation and i have to know at what point of the process does it become obvious that there is only one

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: i have -16x^2+88x+3=124 and i have to use the quadratic formula to solve the equation and i have to know at what point of the process does it become obvious that there is only one       Log On


   

Question 241788: i have -16x^2+88x+3=124 and i have to use the quadratic formula to solve the equation and i have to know at what point of the process does it become obvious that there is only one solution to this equation?
Found 2 solutions by JimboP1977, checkley77:
Answer by JimboP1977(311) About Me  (Show Source):
You can put this solution on YOUR website!
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
If the b%5E2-4ac is equal to zero then there is only one solution.
The general form of the quadratic is ax%5E2%2Bbx%2Bc=0
You need to rearrange your equation to that form.
so -16x%5E2%2B88x-121=0
So for your equation we have b=88 a=-16 and c=-121
88%5E2-%284%2A-16%2A-121%29=0 At this point you know there is only one solution.

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
-16x^2+88x+3=124
-16x^2+88x+3-124=0
16x^2-88x+121=0 here you have 16=4^2 & 121=11^2 & 2*4*11=88.
This identifies a single solution.
(4x-11)^2=0
4x-11=0
x=11
x=11/4 ans.
Proof:
16(11/4)^2-88(11/4)+121=0
16*121/16-968/4+121=0
121-242+121=0
121-242+121=0
242-242=0
0=0