SOLUTION: do you now gow to write an equation of a parabola with a max value of 4 when x is 1 and one x intercept at 2... help with this specific and ones similar to it please
Question 240464: do you now gow to write an equation of a parabola with a max value of 4 when x is 1 and one x intercept at 2... help with this specific and ones similar to it please Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! do you now how to write an equation of a parabola with a max value of 4 when x is 1 and one x intercept at 2... help with this specific and ones similar to it please
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Vertex: (1,4)
x-intercept: (2,0)
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Form:
(x-1)^2 = 4p(y-4)
Solve for "p":
(2-1)^2 = 4p(0-4)
-16p = 1
p = -1/16
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Equation:
(x-1)^2 = 4(-1/16)(y-4)
x^2-2x+1 = (-1/4)(y-4)
(-1/4)y + 1 = x^2-2x+1
(-1/4)y = x^2-2x
y = -4x^2+8x
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Cheers,
Stan H.
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