SOLUTION: how would you graph the following fuctions? 1) y=1/2(x-3)2 +1 and y=-(x+4)2 -5 ?

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Question 23682: how would you graph the following fuctions?
1) y=1/2(x-3)2 +1
and y=-(x+4)2 -5 ?
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
You probably already know that the graph of y+=+x%5E2 looks like this:
+graph%28300%2C300%2C+-10%2C+10%2C-10%2C+10%2C+x%5E2+%29

Well, these graphs will be similar, but because of the (x-3) you will be moving the graph of y =x^2 to the RIGHT 3 units. Because of the +1 added to the end of the equation, the graph will be moved UP 1 unit. And because of the 1/2 coefficient, it opens up the graph and makes it wider.
graph+%28400%2C400%2C+-10%2C10%2C-10%2C10%2C+%281%2F2%29%2A%28x-3%29%5E2+%2B1%29+

For your second graph, it says y=-%28x%2B4%29%5E2+-5, the (x+4) moves the graph to the LEFT 4, the -5 at the end of the equation moves the graph DOWN 5 units, and the negative coefficient in front of the squared term INVERTS the graph! It should look like this:
graph+%28400%2C400%2C+-10%2C10%2C-10%2C10%2C-%28x%2B4%29%5E2+-5%29

R^2 at SCC