SOLUTION: The Everton college store paid $1903 for an order of 49 calculators.The store paid $11 for each scientific calculaor. The others,all graphing calculators,cost the store $55 each.

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Question 236055: The Everton college store paid $1903 for an order of 49 calculators.The store paid $11 for each scientific calculaor. The others,all graphing calculators,cost the store $55 each. How many types of each calculator was ordered?
Found 2 solutions by stanbon, jojo14344:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The Everton college store paid $1903 for an order of 49 calculators.The store paid $11 for each scientific calculaor. The others,all graphing calculators,cost the store $55 each. How many types of each calculator was ordered?
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Quantity Equation: c + g = 49
Value Equation::: 11c+55g = 1903
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Multiply thru the Quantity Equation by 11 to get:
11c + 11g = 11*49
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Subtract that Eq. from the Value Eq and solve for "g":
44g = 1903-11*49
g = 31 (# of graphing calculators bought)
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Since c+g = 49, c = 18 (# of sci. calculators bought)
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Cheers,
Stan H.

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!


Let x= SC
and y=GC
Then,
11%28x%29%2B55%28y%29=1903, EQN 1

Also we know,
x%2By=49, EQN 2
we get, x=49-y, EQN 3, subst. in EQN 1

11%28highlight%2849-y%29%29%2B55y=1903
539-11y%2B55y=1903
44y-1903-539=1364 ----> cross%2844%29y%2Fcross%284%29=cross%281364%2931%2Fcross%2844%29
red%28y=31%29, number of GC, subst, in EQN 3

x=49-31=red%2818%29, number of SC

Check via EQN 1:
11%2818%29%2B55%2831%29=1903
198%2B1705=1903
1903=1903

Thank you,
Jojo