SOLUTION: There are three ways for solutions to exist. 1.No Solutions 2.One Solution 3.Two Solutions Please find the number of solution for the following equation based on your respons

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: There are three ways for solutions to exist. 1.No Solutions 2.One Solution 3.Two Solutions Please find the number of solution for the following equation based on your respons      Log On


   

Question 234900: There are three ways for solutions to exist.
1.No Solutions
2.One Solution
3.Two Solutions
Please find the number of solution for the following equation based on your response to the above statement.
x^2 - 3x + 2 = 0.
Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
Given: X%5E2+-3X+%2B+2+=+0
This equation can be foiled
%28X-1%29%2A%28X-2%29+=+0
Then you get 2 solutions.
X-1 = 0 or rewritten as X = 1
& X-2 = 0 or rewritten as X = 2